Optimal. Leaf size=133 \[ \frac{35 i a^4 \sec (c+d x)}{8 d}+\frac{35 a^4 \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{7 i \sec (c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{12 d}+\frac{35 i \sec (c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{24 d}+\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^3}{4 d} \]
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Rubi [A] time = 0.0956145, antiderivative size = 133, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 3, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.136, Rules used = {3498, 3486, 3770} \[ \frac{35 i a^4 \sec (c+d x)}{8 d}+\frac{35 a^4 \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{7 i \sec (c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{12 d}+\frac{35 i \sec (c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{24 d}+\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^3}{4 d} \]
Antiderivative was successfully verified.
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Rule 3498
Rule 3486
Rule 3770
Rubi steps
\begin{align*} \int \sec (c+d x) (a+i a \tan (c+d x))^4 \, dx &=\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^3}{4 d}+\frac{1}{4} (7 a) \int \sec (c+d x) (a+i a \tan (c+d x))^3 \, dx\\ &=\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^3}{4 d}+\frac{7 i \sec (c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{12 d}+\frac{1}{12} \left (35 a^2\right ) \int \sec (c+d x) (a+i a \tan (c+d x))^2 \, dx\\ &=\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^3}{4 d}+\frac{7 i \sec (c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{12 d}+\frac{35 i \sec (c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{24 d}+\frac{1}{8} \left (35 a^3\right ) \int \sec (c+d x) (a+i a \tan (c+d x)) \, dx\\ &=\frac{35 i a^4 \sec (c+d x)}{8 d}+\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^3}{4 d}+\frac{7 i \sec (c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{12 d}+\frac{35 i \sec (c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{24 d}+\frac{1}{8} \left (35 a^4\right ) \int \sec (c+d x) \, dx\\ &=\frac{35 a^4 \tanh ^{-1}(\sin (c+d x))}{8 d}+\frac{35 i a^4 \sec (c+d x)}{8 d}+\frac{i a \sec (c+d x) (a+i a \tan (c+d x))^3}{4 d}+\frac{7 i \sec (c+d x) \left (a^2+i a^2 \tan (c+d x)\right )^2}{12 d}+\frac{35 i \sec (c+d x) \left (a^4+i a^4 \tan (c+d x)\right )}{24 d}\\ \end{align*}
Mathematica [A] time = 1.21507, size = 237, normalized size = 1.78 \[ -\frac{a^4 \sec ^4(c+d x) \left (3 \left (42 \sin (c+d x)+58 \sin (3 (c+d x))-128 i \cos (3 (c+d x))+35 \cos (4 (c+d x)) \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+105 \log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )+140 \cos (2 (c+d x)) \left (\log \left (\cos \left (\frac{1}{2} (c+d x)\right )-\sin \left (\frac{1}{2} (c+d x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )-35 \cos (4 (c+d x)) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )-105 \log \left (\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )\right )\right )-896 i \cos (c+d x)\right )}{192 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.028, size = 231, normalized size = 1.7 \begin{align*}{\frac{{a}^{4} \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}-{\frac{{a}^{4} \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{8\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{{a}^{4} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{8\,d}}-{\frac{27\,{a}^{4}\sin \left ( dx+c \right ) }{8\,d}}+{\frac{35\,{a}^{4}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}}-{\frac{{\frac{4\,i}{3}}{a}^{4} \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{d \left ( \cos \left ( dx+c \right ) \right ) ^{3}}}+{\frac{{\frac{4\,i}{3}}{a}^{4} \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{d\cos \left ( dx+c \right ) }}+{\frac{{\frac{4\,i}{3}}{a}^{4}\cos \left ( dx+c \right ) \left ( \sin \left ( dx+c \right ) \right ) ^{2}}{d}}+{\frac{{\frac{8\,i}{3}}{a}^{4}\cos \left ( dx+c \right ) }{d}}-3\,{\frac{{a}^{4} \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}+{\frac{4\,i{a}^{4}}{d\cos \left ( dx+c \right ) }} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.1867, size = 243, normalized size = 1.83 \begin{align*} \frac{3 \, a^{4}{\left (\frac{2 \,{\left (5 \, \sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1} + 3 \, \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 72 \, a^{4}{\left (\frac{2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} + \log \left (\sin \left (d x + c\right ) + 1\right ) - \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 48 \, a^{4} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + \frac{192 i \, a^{4}}{\cos \left (d x + c\right )} + \frac{64 i \,{\left (3 \, \cos \left (d x + c\right )^{2} - 1\right )} a^{4}}{\cos \left (d x + c\right )^{3}}}{48 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.19609, size = 717, normalized size = 5.39 \begin{align*} \frac{558 i \, a^{4} e^{\left (7 i \, d x + 7 i \, c\right )} + 1022 i \, a^{4} e^{\left (5 i \, d x + 5 i \, c\right )} + 770 i \, a^{4} e^{\left (3 i \, d x + 3 i \, c\right )} + 210 i \, a^{4} e^{\left (i \, d x + i \, c\right )} + 105 \,{\left (a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} + 4 \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} + 6 \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 4 \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} + a^{4}\right )} \log \left (e^{\left (i \, d x + i \, c\right )} + i\right ) - 105 \,{\left (a^{4} e^{\left (8 i \, d x + 8 i \, c\right )} + 4 \, a^{4} e^{\left (6 i \, d x + 6 i \, c\right )} + 6 \, a^{4} e^{\left (4 i \, d x + 4 i \, c\right )} + 4 \, a^{4} e^{\left (2 i \, d x + 2 i \, c\right )} + a^{4}\right )} \log \left (e^{\left (i \, d x + i \, c\right )} - i\right )}{24 \,{\left (d e^{\left (8 i \, d x + 8 i \, c\right )} + 4 \, d e^{\left (6 i \, d x + 6 i \, c\right )} + 6 \, d e^{\left (4 i \, d x + 4 i \, c\right )} + 4 \, d e^{\left (2 i \, d x + 2 i \, c\right )} + d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} a^{4} \left (\int - 6 \tan ^{2}{\left (c + d x \right )} \sec{\left (c + d x \right )}\, dx + \int \tan ^{4}{\left (c + d x \right )} \sec{\left (c + d x \right )}\, dx + \int 4 i \tan{\left (c + d x \right )} \sec{\left (c + d x \right )}\, dx + \int - 4 i \tan ^{3}{\left (c + d x \right )} \sec{\left (c + d x \right )}\, dx + \int \sec{\left (c + d x \right )}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.33787, size = 236, normalized size = 1.77 \begin{align*} \frac{105 \, a^{4} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) + 1 \right |}\right ) - 105 \, a^{4} \log \left ({\left | \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 1 \right |}\right ) - \frac{2 \,{\left (81 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{7} + 96 i \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{6} - 105 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{5} - 480 i \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{4} - 105 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{3} + 544 i \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} + 81 \, a^{4} \tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right ) - 160 i \, a^{4}\right )}}{{\left (\tan \left (\frac{1}{2} \, d x + \frac{1}{2} \, c\right )^{2} - 1\right )}^{4}}}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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